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NBA: Bucks oust Celtics

Published May 9, 2019 12:00 am
Milwaukee became the first team to reach the NBA's final four as the top-seeded Bucks beat the visiting Boston Celtics with a 116-91 series-clinching victory on Wednesday. The Bucks used balanced scoring and a stingy defense to eliminate the fourth-seeded Celtics in five games, avenging a seven-game first round loss to Boston last season. The Celtics had reached the NBA semi-finals against the Cleveland Cavaliers each of the last two seasons. It marks the first time since 1983 that the Bucks have won a playoff series against the Celtics, who won the first game in this year's series before dropping four consecutive contests. Giannis Antetokounmpo #34 of the Milwaukee Bucks handles the ball against the Boston Celtics (Nathaniel S. Butler / NBAE / Getty Images / AFP) Giannis Antetokounmpo #34 of the Milwaukee Bucks handles the ball against the Boston Celtics (Nathaniel S. Butler / NBAE / Getty Images / AFP) Milwaukee advances to the Eastern Conference finals, where they will have the home-court advantage over the winner of the other East second round series between the Toronto Raptors and the Philadelphia 76ers. They meet in a game six in Philadelphia on Thursday, with the second-seeded Raptors holding a 3-2 lead. (AFP)
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